Gravitational Constant

G
Universal Constant
$6.67430(15) \times 10^{-11}$ m³ kg⁻¹ s⁻²
Dimensions: L³ M⁻¹ T⁻²  ·  Relative uncertainty: $2.2 \times 10^{-5}$
At a glance
Expressed in Planck units, $G$ can be written as the product of two factors: a length-per-mass ratio $l_\mathrm{P}/m_\mathrm{P}$ and a velocity squared $c^2$. These two factors are functionally separable in gravitational formulas. Where a formula calculates the velocity or momentum of a body in a gravitational field, $c^2$ participates directly, setting the velocity-squared scale. Where only spatial geometry matters — as in the Schwarzschild radius — $c^2$ cancels out and only the length-per-mass ratio remains.

Universal form

The complete Planck-unit decomposition of $G$ is:

Gravitational constant in Planck units
$$G = \frac{l_\mathrm{P}^3}{m_\mathrm{P} \, t_\mathrm{P}^2}$$

This groups naturally into two factors:

$$G = \frac{l_\mathrm{P}}{m_\mathrm{P}} \cdot \frac{l_\mathrm{P}^2}{t_\mathrm{P}^2} = \frac{l_\mathrm{P}}{m_\mathrm{P}} \cdot c^2$$
Dimensions
The ratio $l_\mathrm{P}/m_\mathrm{P}$ contributes L M⁻¹. The factor $c^2 = l_\mathrm{P}^2/t_\mathrm{P}^2$ contributes L² T⁻². Combined: L³ M⁻¹ T⁻².

Equivalent expressions

The same dimensional content can be grouped into different combinations of Planck-scale quantities, each foregrounding a different physical aspect.

Length-per-mass × velocity squared

$$G = \frac{l_\mathrm{P}}{m_\mathrm{P}} \cdot c^2$$

The most physically transparent form. The ratio $l_\mathrm{P}/m_\mathrm{P}$ sets the gravitational coupling; $c^2$ provides the velocity or energy scale.

Planck force × (length-per-mass)²

$$G = F_\mathrm{P} \left(\frac{l_\mathrm{P}}{m_\mathrm{P}}\right)^2$$

where $F_\mathrm{P} = c^4/G = m_\mathrm{P} c^2/l_\mathrm{P}$ is the Planck force. This shows $G$ as the Planck force scaled by the square of the gravitational coupling ratio.

Planck acceleration × area-per-mass

$$G = a_\mathrm{P} \cdot \frac{l_\mathrm{P}^2}{m_\mathrm{P}}$$

where $a_\mathrm{P} = c^2/l_\mathrm{P}$ is the Planck acceleration.

Planck energy × length per mass²

$$G = E_\mathrm{P} \cdot \frac{l_\mathrm{P}}{m_\mathrm{P}^2}$$

where $E_\mathrm{P} = m_\mathrm{P} c^2$ is the Planck energy. This form appears naturally when $G$ enters energy expressions.

Quantum form

$$G = \frac{\hbar c}{m_\mathrm{P}^2}$$

This relates $G$ directly to $\hbar$ and $c$ through the Planck mass and is the relationship inverted in the customary calculation $m_\mathrm{P} = \sqrt{\hbar c/G}$.


Dimensional verification

Because $G$ contains three Planck-unit components in its dimensions — a Planck length cubed divided by a Planck mass and a Planck time squared — its universal form is $l_\mathrm{P}^3/(m_\mathrm{P} t_\mathrm{P}^2)$. The compound constants $c$, $\hbar$, and $G$ are customarily used to calculate Planck-unit values, but they are not the only combination that works. The electromagnetic constants $\varepsilon_0$ or $\mu_0$ — which likewise contain Planck units in their dimensions — can be combined with $G$, $c$, and $e$ to recover the same values, at the cost of carrying a factor of the fine-structure constant $\alpha$.

Algebraic rearrangements of the Planck-unit composition of $G$ each yield the same result:

$$G = \frac{l_\mathrm{P}^2 \, c^3}{\hbar} \qquad G = \frac{\hbar \, c}{m_\mathrm{P}^2} \qquad G = \frac{t_\mathrm{P}^2 \, c^5}{\hbar}$$

Decomposing any of these into elemental Planck units produces the same result: $l_\mathrm{P}^3/(m_\mathrm{P} \, t_\mathrm{P}^2)$.


Physical characterization

The decomposition $G = (l_\mathrm{P}/m_\mathrm{P}) \cdot c^2$ reveals that the constant packages two ingredients that play functionally separable roles in gravitational formulas. Tracing units through specific calculations makes this concrete.

The gravitational potential parameter

The combination $GM/r$ appears throughout gravitational physics. Substituting the universal form of $G$:

$$\frac{GM}{r} = \frac{l_\mathrm{P}}{m_\mathrm{P}} \cdot c^2 \cdot \frac{M}{r} = c^2 \cdot \frac{M}{m_\mathrm{P}} \cdot \frac{l_\mathrm{P}}{r}$$

The dimensional ratio $l_\mathrm{P}/m_\mathrm{P}$, combined with $M$ and $1/r$, has naturally separated into two dimensionless but physically characteristic ratios: $M/m_\mathrm{P}$ (the source mass measured in Planck masses) and $l_\mathrm{P}/r$ (the Planck length measured against the distance). Their product is the dimensionless gravitational potential parameter, and $c^2$ provides the scale.

In the Schwarzschild solution, the metric depends entirely on this single quantity:

$$\frac{r_s}{r} = \frac{2GM}{c^2 r} = 2 \cdot \frac{M}{m_\mathrm{P}} \cdot \frac{l_\mathrm{P}}{r}$$

Where the squared speed of light participates: orbital velocity

The orbital velocity demonstrates how $c^2$ from $G$ becomes the velocity of a second body:

$$v_o = \sqrt{\frac{GM}{r}} = c \sqrt{\frac{M}{m_\mathrm{P}} \cdot \frac{l_\mathrm{P}}{r}}$$

The $c^2$ inside $G$ has become $v_o^2$. The orbital velocity as a fraction of $c$ equals the square root of the dimensionless potential parameter.

Numerical verification — Earth’s orbit (1 AU)
$M_\odot/m_\mathrm{P}$$9.13 \times 10^{37}$
$l_\mathrm{P}/r$$1.08 \times 10^{-46}$
Orbital velocity$v_o/c = \sqrt{9.86 \times 10^{-9}} = 9.93 \times 10^{-5}$, so $v_o = 29.8$ km/s

Where the squared speed of light cancels: the Schwarzschild radius

The Schwarzschild radius demonstrates the opposite case — a formula that draws on $G$ but discards the $c^2$:

$$r_s = \frac{2GM}{c^2} = 2 \cdot \frac{l_\mathrm{P}}{m_\mathrm{P}} \cdot c^2 \cdot \frac{M}{c^2} = 2 l_\mathrm{P} \cdot \frac{M}{m_\mathrm{P}}$$

The $c^2$ in $G$ cancels with the $c^2$ in the denominator. The Schwarzschild radius does not describe the velocity or momentum of a second body — it is a geometric property of the source mass alone. The formula retains only $l_\mathrm{P}/m_\mathrm{P}$, producing a pure length proportional to the mass ratio.

Numerical verification — the Sun
Schwarzschild radius$r_s = 2 \times 1.616 \times 10^{-35} \times 9.13 \times 10^{37} = 2.95$ km

The pattern

This pattern recurs throughout gravitational physics. The constant $G = (l_\mathrm{P}/m_\mathrm{P}) \cdot c^2$ supplies both a geometric coupling ($l_\mathrm{P}/m_\mathrm{P}$) and a velocity-squared scale ($c^2$). Different formulas draw on these ingredients differently.

Where velocity or momentum is being calculated, $c^2$ participates directly — becoming $v^2$ or contributing to kinetic energy. Where only spatial geometry matters, $c^2$ cancels, leaving the length-per-mass ratio alone. Recognizing which piece of $G$ contributes to which piece of the answer transforms dimensional analysis into a map of the physics.


The constant in context

The following formulas show $G$ at work across different physical settings.

Gravitational acceleration

$$g = \frac{GM}{r^2} = \frac{c^2}{r} \cdot \frac{M}{m_\mathrm{P}} \cdot \frac{l_\mathrm{P}}{r}$$

An acceleration — a fraction of $c^2/r$ determined by the dimensionless potential parameter. At Earth’s surface: $M_\oplus/m_\mathrm{P} = 2.74 \times 10^{32}$ and $l_\mathrm{P}/R_\oplus = 2.54 \times 10^{-42}$, giving $g = 9.8$ m/s².

Escape velocity

$$v_e = \sqrt{\frac{2GM}{r}} = c\sqrt{\frac{2M}{m_\mathrm{P}} \cdot \frac{l_\mathrm{P}}{r}} = c\sqrt{\frac{r_s}{r}}$$

The $c^2$ from $G$ becomes $v^2$. The escape velocity as a fraction of $c$ is the square root of the Schwarzschild ratio $r_s/r$.

Gravitational potential energy

$$U = -\frac{GMm}{r} = -mc^2 \cdot \frac{M}{m_\mathrm{P}} \cdot \frac{l_\mathrm{P}}{r}$$

The $c^2$ from $G$ combines with the test mass $m$ to produce the rest energy $mc^2$. The dimensionless potential parameter determines what fraction of the rest energy is gravitational binding energy.

Kepler’s third law

$$T^2 = \frac{4\pi^2 r^3}{GM}$$

The orbital period depends on the gravitational parameter $GM$, which is what observations actually measure — and they measure it far more precisely than $G$ alone.

Gravitational wave luminosity

$$L_{\scriptscriptstyle GW} = \frac{32}{5} \frac{G^4}{c^5} \frac{m_1^2 m_2^2 (m_1 + m_2)}{r^5}$$

In the strong-field regime, multiple powers of $G$ and $c$ appear. The ratio $G/c^2 = l_\mathrm{P}/m_\mathrm{P}$ is the characteristic coupling scale.


Why this value?

$G$ is the least precisely measured of the fundamental constants. Its current relative uncertainty of $2.2 \times 10^{-5}$ is orders of magnitude larger than that of $\hbar$, $c$, or $\alpha$. This is not a failure of experimental effort — it is intrinsic. Gravity is extraordinarily weak at laboratory scales, and $G$ can only be measured through gravitational experiments. There is no electromagnetic or quantum proxy.

The gravitational parameter $GM$ for astronomical bodies is known to far higher precision than $G$ itself. The product $GM_\odot$ is determined from planetary ephemerides to 11 significant figures, while $G$ alone is known to only 5. This is because gravitational experiments always measure $G$ multiplied by a mass; extracting $G$ requires an independent mass measurement, which is where precision is lost.

In SI units, $G$ is numerically small: $6.674 \times 10^{-11}$. This reflects the large value of the Planck mass — about 22 micrograms — relative to elementary particle masses. The ratio $m_\mathrm{P}/m_e \approx 2.4 \times 10^{22}$ means that gravitational effects between particles are suppressed by factors of order $(m/m_\mathrm{P})^2 \sim 10^{-45}$ relative to electromagnetic effects. Why $m_\mathrm{P}$ is so much larger than particle masses — equivalently, why gravity is so weak — remains one of the central open questions in physics.

Unlike $\alpha$, whose value is dimensionless and therefore physically meaningful in an absolute sense, the numerical value of $G$ depends on our choice of units. What is physically meaningful is the dimensionless ratio it produces in any given context: the gravitational potential parameter $(M/m_\mathrm{P})(l_\mathrm{P}/r)$.


Connections

The Planck mass: $\displaystyle m_\mathrm{P} = \sqrt{\frac{\hbar c}{G}}$ — the mass at which gravitational and quantum scales converge.

The Planck force: $\displaystyle F_\mathrm{P} = \frac{c^4}{G}$ — a Planck unit that involves neither $\hbar$ nor charge, making it purely classical-gravitational.

Einstein’s gravitational constant: $\displaystyle \kappa = \frac{8\pi G}{c^4}$ — the coupling constant of general relativity.

The Planck length: $\displaystyle l_\mathrm{P} = \sqrt{\frac{\hbar G}{c^3}}$    The Planck time: $\displaystyle t_\mathrm{P} = \sqrt{\frac{\hbar G}{c^5}}$