Why are there so many electromagnetic unit systems?

The elementary charge has three numerical values in use today. In SI units, $e = 1.602 \times 10^{-19}$ coulombs. In the electromagnetic CGS system (emu), $e = 1.602 \times 10^{-20}$ abcoulombs. In the electrostatic CGS system (esu), $e = 4.803 \times 10^{-10}$ statcoulombs. Three numbers, three units, the same physical charge. The story of how this happened — and what Planck-unit decomposition reveals about it — is one of the cleanest examples of what can become visible when a formula is written in universal units.

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Where this article goes
We trace the CGS/SI split back to a single dimensional identity: $\mu_{0}/(4\pi) = l_{\mathrm{P}} m_{\mathrm{P}} / q_{\mathrm{P}}^{2}$. Nineteenth-century physicists had to express charge through mechanical effects because they did not yet know there was an indivisible unit of it. Two different mechanical effects — the magnetic force between currents, and the electrostatic force between charges — gave two different ways to define charge, and so the emu/esu split emerged. Planck-unit decomposition shows the three systems as three ways to dispose of the same Planck-charge degree of freedom.

Why there are three units at all

In the SI system, electric charge has its own fundamental dimension — the coulomb — independent of mass, length, and time. In the CGS systems (both emu and esu), charge does not have its own dimension. Charge is expressed entirely in mechanical units: grams, centimeters, and seconds. This was not a stylistic choice. Before Millikan’s 1909 oil-drop experiment, physicists did not have a reliable handle on the elementary charge, and there was no compelling reason to treat charge as a separate fundamental dimension. It had to be derived from the force laws that involved it.

There are two such force laws, and they give two different mechanical expressions for charge. The esu derivation starts from Coulomb’s law, and reads off the dimensions of charge from the electrostatic force between two stationary charges. The emu derivation starts from Ampère’s force law, and reads off the dimensions of current from the magnetic force between two parallel wires. Both are self-consistent. They disagree about the units because electrostatics and magnetostatics contain a factor of $c^{2}$ between them — the same factor of $c^{2}$ that appears in every relativistic rewriting of Maxwell’s equations.

The Planck-unit identity

The simplest way to see what the different systems are doing is to write the magnetic constant in Planck-unit form. Starting from the natural decomposition (EJP 2024 eq. 43):

Magnetic constant in Planck-unit form
$$\frac{\mu_{0}}{4\pi} \;=\; \frac{F_{\mathrm{P}}}{I_{\mathrm{P}}^{2}} \;=\; \frac{l_{\mathrm{P}}\, m_{\mathrm{P}}}{q_{\mathrm{P}}^{2}} \;=\; 10^{-7}\;\mathrm{kg\,m\,C^{-2}}$$

The middle expression treats $\mu_{0}/(4\pi)$ as force per current squared; the right-hand form rewrites the current as charge per time, giving the combination of Planck units $l_{\mathrm{P}} m_{\mathrm{P}} / q_{\mathrm{P}}^{2}$. Numerically, $\mu_{0}/(4\pi)$ is exactly $10^{-7}\;\mathrm{N\,A^{-2}}$ in pre-2019 SI, essentially $10^{-7}$ in post-2019 SI, and whatever you set it to in CGS. This identity is the single sentence out of which the emu and esu systems fall.

Numerical check — $\mu_{0}/(4\pi)$
$l_{\mathrm{P}} m_{\mathrm{P}}$$= 1.616255\times 10^{-35}\cdot 2.176434\times 10^{-8}$→$= 3.5177 \times 10^{-43}\;\mathrm{kg\,m}$
$q_{\mathrm{P}}^{2}$$= (1.875546\times 10^{-18})^{2}$→$= 3.5177 \times 10^{-36}\;\mathrm{C^{2}}$
$l_{\mathrm{P}} m_{\mathrm{P}} / q_{\mathrm{P}}^{2}$$= 1.000\times 10^{-7}\;\mathrm{kg\,m\,C^{-2}} \;=\; \mu_{0}/(4\pi)$

The electromagnetic system (emu)

The emu choice is to set the magnetic constant equal to $1$, which immediately gives a definition of charge in mechanical units. Setting $\mu_{0}/(4\pi) = 1$ in the identity above yields:

Charge defined via Ampère’s force law (emu)
$$\frac{l_{\mathrm{P}}\, m_{\mathrm{P}}}{q_{\mathrm{P}}^{2}} = 1 \quad\Longrightarrow\quad q_{\mathrm{P}}^{2} = l_{\mathrm{P}}\, m_{\mathrm{P}} \quad\Longrightarrow\quad [\mathrm{charge}]^{2} = [\mathrm{mass}] \cdot [\mathrm{length}]$$

In this system the abcoulomb has the dimensions $M^{1/2} L^{1/2}$, and the abampere has dimensions $M^{1/2} L^{1/2} T^{-1}$ — the square root of force. The Planck charge in abcoulombs is:

Planck charge in abcoulombs
$q_{\mathrm{P}} = \sqrt{l_{\mathrm{P}} m_{\mathrm{P}}}$$= \sqrt{3.5177\times 10^{-43}\;\mathrm{kg\,m}}$→$= 5.931\times 10^{-22}\;\mathrm{kg^{1/2}\,m^{1/2}}$
convert to cgs ($\mathrm{kg}\to 10^{3}\,\mathrm{g}$, $\mathrm{m}\to 10^{2}\,\mathrm{cm}$)$\times (10^{3}\cdot 10^{2})^{1/2}$→$\times 316.23$
$q_{\mathrm{P}}$ (emu)$= 1.876\times 10^{-19}\;\mathrm{abC}$

The conversion factor to SI coulombs is exactly $10$: $1\;\mathrm{abC} = 10\;\mathrm{C}$. This factor is not mysterious — it is the square root of the $10^{-2}\;\mathrm{cm\,g\,C^{-2}}$ value that the pre-SI CGS system had for $\mu_{0}/(4\pi)$, compared to the emu value of $1$. The two systems disagree on the numerical value of $\mu_{0}/(4\pi)$, and the unit of charge absorbs the difference.

The electrostatic system (esu)

The esu choice is to set the electric constant (rather than the magnetic one) equal to a fixed value. Starting from the Coulomb constant in Planck-unit form:

Coulomb constant in Planck-unit form
$$\frac{1}{4\pi\varepsilon_{0}} \;=\; \frac{F_{\mathrm{P}}\, l_{\mathrm{P}}^{2}}{q_{\mathrm{P}}^{2}} \;=\; \frac{l_{\mathrm{P}}\, m_{\mathrm{P}}\, c^{2}}{q_{\mathrm{P}}^{2}}$$

Setting $1/(4\pi\varepsilon_{0}) = 1$ gives a different definition of charge — this time with an extra factor of $c^{2}$ embedded in the mechanical units:

Charge defined via Coulomb’s law (esu)
$$q_{\mathrm{P}}^{2} = l_{\mathrm{P}}\, m_{\mathrm{P}}\, c^{2} \quad\Longrightarrow\quad [\mathrm{charge}]^{2} = [\mathrm{energy}] \cdot [\mathrm{length}]$$

The statcoulomb has dimensions $M^{1/2} L^{3/2} T^{-1}$: the square root of energy times length. The numerical Planck charge in statcoulombs is the abcoulomb value multiplied by $c$ in cgs units:

Planck charge in statcoulombs
$q_{\mathrm{P}}$ (emu)$= 1.876\times 10^{-19}\;\mathrm{abC}$
$\times c$ (cgs)$\times 2.998\times 10^{10}\;\mathrm{cm/s}$→$\times 2.998\times 10^{10}$
$q_{\mathrm{P}}$ (esu)$= 5.623\times 10^{-9}\;\mathrm{statC}$

The conversion factor to coulombs is $1\;\mathrm{C} = 2.998 \times 10^{9}\;\mathrm{statC}$ — that is $c$ with the conventional factor of $10$. The numerical coincidence that the emu-to-esu conversion factor is exactly the speed of light in cgs units is the same fact that $1/(4\pi\varepsilon_{0}) \cdot 4\pi = \mu_{0} c^{2}$. It is the single factor of $c^{2}$ that separates electrostatics from magnetostatics.

Three systems, one structure

SystemDimensional choiceCharge definition$q_{\mathrm{P}}$ numerical
SI (post-2019)charge is fundamentalcoulomb defined via fixed $e$$1.876\times 10^{-18}\;\mathrm{C}$
emu (CGS)$\mu_{0}/(4\pi) = 1$$[\mathrm{charge}]^{2} = [\mathrm{mass}][\mathrm{length}]$$1.876\times 10^{-19}\;\mathrm{abC}$
esu (CGS, Gaussian)$1/(4\pi\varepsilon_{0}) = 1$$[\mathrm{charge}]^{2} = [\mathrm{energy}][\mathrm{length}]$$5.623\times 10^{-9}\;\mathrm{statC}$
Universal units$q_{\mathrm{P}}$ as natural scale$e/q_{\mathrm{P}} = \sqrt{\alpha}$$0.0854$ (dimensionless)

Each row is a different way to dispose of the same Planck-charge degree of freedom. The bottom row is what the other three have in common: the ratio $e / q_{\mathrm{P}} = \sqrt{\alpha}$ is the same number in every system, independent of whether charge is expressed in coulombs, abcoulombs, or statcoulombs. That invariant dimensionless ratio is the physical content; the three unit systems are different conventions for packaging it.

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What the decomposition reveals
The emu and esu systems look complicated because they encode a physical fact — $\mu_{0}/(4\pi) = l_{\mathrm{P}} m_{\mathrm{P}} / q_{\mathrm{P}}^{2}$ — by fiat, through a choice of units. Setting $\mu_{0}/(4\pi) = 1$ forces charge-squared to carry the dimensions of mass times length; setting $1/(4\pi\varepsilon_{0}) = 1$ forces it to carry the dimensions of energy times length, which differ by $c^{2}$. In either CGS system, the numerical value of the Planck charge (or the elementary charge) is adjusted to match the chosen dimensional assignment. The SI system, and its universal-unit equivalent, treat charge as its own fundamental dimension and absorb the conversion factors into $\mu_{0}$ and $\varepsilon_{0}$ explicitly. The dimensionless ratio $e/q_{\mathrm{P}} = \sqrt{\alpha}$ is unaffected by any of these choices.

Why the Planck-charge reading is the clean one

The historical CGS systems were trying to eliminate charge as a fundamental dimension because its natural scale was unknown. Once Millikan’s measurement established that an indivisible charge exists, the motivation for deriving charge from mechanical dimensions disappeared — but the systems remained in use because they were convenient for electrodynamics textbooks and because conversion tables were already familiar. The 2019 SI redefinition fixed $e$ exactly, making the coulomb a defined multiple of the elementary charge. The Planck-charge reading goes one step further and treats $q_{\mathrm{P}}$ as the reference scale, with $e/q_{\mathrm{P}} = \sqrt{\alpha} = 0.08542…$ as the unit-invariant coupling ratio.

Viewed through this lens, the emu and esu systems are not wrong; they are two different Planck-unit packagings of the same physics, each one having absorbed a factor of $\sqrt{l_{\mathrm{P}} m_{\mathrm{P}}}$ or $\sqrt{l_{\mathrm{P}} m_{\mathrm{P}}}\cdot c$ into its unit of charge. The emu charge unit is $\sqrt{l_{\mathrm{P}} m_{\mathrm{P}}}$ in universal form; the esu charge unit is $\sqrt{l_{\mathrm{P}} m_{\mathrm{P}} c^{2}}$. The three-unit history is an accident of which mechanical force law was given unit-one priority.

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The takeaway
The reason physics has three different units for the elementary charge is that 19th-century physicists didn’t know charge was a fundamental dimension — they had to define it through one of two mechanical force laws, and the two laws differ by a factor of $c^{2}$. The Planck-charge identity $\mu_{0}/(4\pi) = l_{\mathrm{P}} m_{\mathrm{P}} / q_{\mathrm{P}}^{2}$ makes this visible in a single line. The dimensionless ratio $e/q_{\mathrm{P}} = \sqrt{\alpha}$ is what all three systems agree on, because it is the only part of the story that has nothing to do with choice of units.

Further reading on this site: the elementary charge profile develops $e = \sqrt{\alpha}\, q_{\mathrm{P}}$ in detail, and the Planck charge profile covers $q_{\mathrm{P}}$ as the base Planck unit of charge. The published source is EJP 2024, “Understanding the natural units,” Section 4.4 and equations 43–51.